ConceptComplete

Cauchy Sequences

A Cauchy sequence is one whose terms become arbitrarily close to each other as the sequence progresses. In complete metric spaces like R\mathbb{R}, Cauchy sequences are precisely the convergent sequences β€” this equivalence is the Cauchy completeness criterion. Cauchy's definition (1821) provides an intrinsic characterization of convergence without reference to the limit.


Definition

Definition2.1Cauchy sequence

A sequence (an)(a_n) in R\mathbb{R} is Cauchy if for every ϡ>0\epsilon > 0, there exists N∈NN \in \mathbb{N} such that

∣amβˆ’an∣<Ο΅forΒ allΒ m,nβ‰₯N.|a_m - a_n| < \epsilon \quad \text{for all } m, n \geq N.

RemarkIntuition

A Cauchy sequence has terms that cluster together: for large enough mm and nn, ama_m and ana_n are within Ο΅\epsilon of each other. Unlike convergence (which requires knowledge of the limit), the Cauchy condition is checkable using only the sequence terms.

Example1/n is Cauchy

Let an=1/na_n = 1/n. For m,nβ‰₯Nm, n \geq N,

∣1mβˆ’1nβˆ£β‰€1m+1n≀2N.\left|\frac{1}{m} - \frac{1}{n}\right| \leq \frac{1}{m} + \frac{1}{n} \leq \frac{2}{N}.

Given Ο΅>0\epsilon > 0, choose NN such that 2/N<Ο΅2/N < \epsilon. Then ∣amβˆ’an∣<Ο΅|a_m - a_n| < \epsilon for all m,nβ‰₯Nm, n \geq N. So (an)(a_n) is Cauchy.

ExamplePartial sums of harmonic series are not Cauchy

Let sn=1+1/2+1/3+β‹―+1/ns_n = 1 + 1/2 + 1/3 + \cdots + 1/n. Then (sn)(s_n) is not Cauchy. For m=2nm = 2n and nn,

∣s2nβˆ’sn∣=1n+1+1n+2+β‹―+12nβ‰₯nβ‹…12n=12.|s_{2n} - s_n| = \frac{1}{n+1} + \frac{1}{n+2} + \cdots + \frac{1}{2n} \geq n \cdot \frac{1}{2n} = \frac{1}{2}.

So ∣smβˆ’sn∣|s_m - s_n| does not go to zero, and (sn)(s_n) is not Cauchy.


Relationship with convergence

Theorem2.1Cauchy Criterion for Convergence

A sequence (an)(a_n) in R\mathbb{R} converges if and only if it is Cauchy.

RemarkProof sketch

(⇒\Rightarrow) If an→La_n \to L, then for large m,nm, n, both ama_m and ana_n are close to LL, hence close to each other.

(⇐\Leftarrow) If (an)(a_n) is Cauchy, it is bounded (proof: choose NN such that ∣amβˆ’an∣<1|a_m - a_n| < 1 for m,nβ‰₯Nm, n \geq N; then all terms lie in a bounded interval). By Bolzano-Weierstrass, (an)(a_n) has a convergent subsequence ankβ†’La_{n_k} \to L. One shows that the full sequence anβ†’La_n \to L using the Cauchy condition.

Full proof: see Cauchy Criterion Proof.

ExampleCauchy sequence converges in R

Let an=βˆ‘k=1n1/k!a_n = \sum_{k=1}^n 1/k!. One can verify (an)(a_n) is Cauchy (terms eventually differ by <Ο΅< \epsilon). By the Cauchy criterion, (an)(a_n) converges in R\mathbb{R}. The limit is eβˆ’1β‰ˆ1.71828e - 1 \approx 1.71828.

ExampleCauchy in Q need not converge in Q

Let an=(1+1/n)na_n = (1 + 1/n)^n (all terms rational). Then (an)(a_n) is Cauchy as a sequence in Q\mathbb{Q} (with the usual metric). However, the limit eβ‰ˆ2.71828…e \approx 2.71828\ldots is irrational, so (an)(a_n) does not converge in Q\mathbb{Q}. This shows Q\mathbb{Q} is not complete.


Properties of Cauchy sequences

Theorem2.2Cauchy sequences are bounded

Every Cauchy sequence is bounded.

Proof

Let (an)(a_n) be Cauchy. Choose NN such that ∣amβˆ’an∣<1|a_m - a_n| < 1 for all m,nβ‰₯Nm, n \geq N. In particular, ∣anβˆ’aN∣<1|a_n - a_N| < 1 for all nβ‰₯Nn \geq N, so ∣an∣<∣aN∣+1|a_n| < |a_N| + 1 for nβ‰₯Nn \geq N. Let

M=max⁑(∣a1∣,∣a2∣,…,∣aNβˆ’1∣,∣aN∣+1).M = \max(|a_1|, |a_2|, \ldots, |a_{N-1}|, |a_N| + 1).

Then ∣anβˆ£β‰€M|a_n| \leq M for all nn.

β– 
RemarkBounded does not imply Cauchy

A bounded sequence need not be Cauchy. For example, an=(βˆ’1)na_n = (-1)^n is bounded but not Cauchy (terms oscillate, so ∣an+1βˆ’an∣=2|a_{n+1} - a_n| = 2 for all nn).

Theorem2.3Algebra of Cauchy sequences

If (an)(a_n) and (bn)(b_n) are Cauchy, then so are (an+bn)(a_n + b_n), (anβˆ’bn)(a_n - b_n), and (anbn)(a_n b_n) (assuming boundedness for the product).

ExampleSum of Cauchy sequences

If (an)(a_n) and (bn)(b_n) are Cauchy, then for large m,nm, n,

∣(am+bm)βˆ’(an+bn)βˆ£β‰€βˆ£amβˆ’an∣+∣bmβˆ’bn∣<Ο΅/2+Ο΅/2=Ο΅.|(a_m + b_m) - (a_n + b_n)| \leq |a_m - a_n| + |b_m - b_n| < \epsilon/2 + \epsilon/2 = \epsilon.

Thus (an+bn)(a_n + b_n) is Cauchy.


Completeness of R

The Cauchy criterion is equivalent to the completeness axiom for R\mathbb{R}.

Theorem2.4Equivalence of completeness notions

The following are equivalent for R\mathbb{R}:

  1. Every nonempty bounded set has a supremum (least upper bound property).
  2. Every Cauchy sequence converges (Cauchy completeness).
  3. Every bounded monotone sequence converges.
RemarkProof strategy

(1) β‡’\Rightarrow (3) is the Monotone Convergence Theorem. (3) β‡’\Rightarrow (2) uses Bolzano-Weierstrass. (2) β‡’\Rightarrow (1) constructs suprema as limits of Cauchy sequences. See Monotone Convergence Theorem and Cauchy Criterion.

ExampleR is the completion of Q

R\mathbb{R} can be defined as the set of equivalence classes of Cauchy sequences in Q\mathbb{Q} (modulo sequences differing by a null sequence). This is the Cauchy completion of Q\mathbb{Q}. Every Cauchy sequence in Q\mathbb{Q} corresponds to a unique real number (its limit in R\mathbb{R}).


Summary

Cauchy sequences provide an intrinsic characterization of convergence:

  • A sequence is Cauchy if terms become arbitrarily close to each other.
  • In R\mathbb{R}, Cauchy sequences are exactly the convergent sequences (Cauchy completeness).
  • In Q\mathbb{Q}, Cauchy sequences need not converge β€” this motivates the construction of R\mathbb{R}.
  • Cauchy completeness is equivalent to the least upper bound property.

See Cauchy Criterion for the proof of the Cauchy criterion, and Metric Spaces for generalizations beyond R\mathbb{R}.