ConceptComplete

Path Independence and Primitives

A central question in complex integration is: when does the integral γf(z)dz\int_\gamma f(z)\,dz depend only on the endpoints and not on the particular path? The answer connects analytic functions, simply connected domains, and the existence of antiderivatives.


Path Independence

Definition3.4Path independence

A continuous function f:DCf: D \to \mathbb{C} on a domain DD is said to have path-independent integrals if for any two contours γ1,γ2\gamma_1, \gamma_2 in DD with the same initial and terminal points, γ1fdz=γ2fdz\int_{\gamma_1} f\,dz = \int_{\gamma_2} f\,dz.

Equivalently, ff has path-independent integrals if and only if γfdz=0\oint_\gamma f\,dz = 0 for every closed contour γ\gamma in DD.

Theorem3.3Equivalence of path independence and existence of primitive

Let f:DCf: D \to \mathbb{C} be continuous on a domain DD. The following are equivalent:

  1. ff has path-independent integrals in DD.
  2. γf(z)dz=0\oint_\gamma f(z)\,dz = 0 for every closed contour γ\gamma in DD.
  3. ff has a primitive (antiderivative) on DD: there exists holomorphic F:DCF: D \to \mathbb{C} with F=fF' = f.
RemarkConstructing the primitive

When path independence holds, the primitive is constructed explicitly by fixing z0Dz_0 \in D and defining

F(z)=z0zf(w)dwF(z) = \int_{z_0}^{z} f(w)\,dw

where the integral is taken along any contour in DD from z0z_0 to zz. The holomorphicity of FF follows from the definition of the complex derivative.


Simply Connected Domains

Definition3.5Simply connected domain

A domain DCD \subseteq \mathbb{C} is simply connected if every closed curve in DD can be continuously deformed to a point within DD. Equivalently, DD is simply connected if CD\mathbb{C} \setminus D is connected (in the Riemann sphere C^\hat{\mathbb{C}}).

Informally, DD is simply connected if it has "no holes."

ExampleSimply connected and non-simply connected domains
  • C\mathbb{C}, any open disk D(z0,r)D(z_0, r), any half-plane, and any convex domain are simply connected.
  • C{0}\mathbb{C} \setminus \{0\} is not simply connected: a circle around the origin cannot be shrunk to a point.
  • An annulus {z:r<z<R}\{z : r < |z| < R\} is not simply connected.
  • A slit plane C(,0]\mathbb{C} \setminus (-\infty, 0] is simply connected, enabling a single-valued branch of logz\log z.

Cauchy's Theorem for Simply Connected Domains

Theorem3.4Cauchy's theorem (simply connected version)

If ff is holomorphic on a simply connected domain DD, then

γf(z)dz=0\oint_\gamma f(z)\,dz = 0

for every closed contour γ\gamma in DD. Consequently, ff has a primitive on DD.

RemarkThe role of topology

Cauchy's theorem reveals a deep interplay between analysis (holomorphicity) and topology (simple connectivity). The failure of Cauchy's theorem on non-simply connected domains is precisely measured by residue theory: γfdz=2πiRes(f,zk)\oint_\gamma f\,dz = 2\pi i \sum \text{Res}(f, z_k).

ExampleLogarithm on a slit plane

On the slit plane D=C(,0]D = \mathbb{C} \setminus (-\infty, 0], the function 1/z1/z is holomorphic and DD is simply connected. By Cauchy's theorem, 1/z1/z has a primitive on DD, namely the principal branch of the logarithm:

Log(z)=lnz+iArg(z),π<Arg(z)<π.\text{Log}(z) = \ln|z| + i\text{Arg}(z), \quad -\pi < \text{Arg}(z) < \pi.

This is well-defined and holomorphic on DD with (Logz)=1/z(\text{Log}\,z)' = 1/z.


Deformation of Contours

Definition3.6Homotopy of curves

Two closed curves γ0,γ1\gamma_0, \gamma_1 in a domain DD are homotopic if there exists a continuous map H:[0,1]×[0,1]DH: [0,1] \times [0,1] \to D such that H(t,0)=γ0(t)H(t,0) = \gamma_0(t), H(t,1)=γ1(t)H(t,1) = \gamma_1(t), and H(0,s)=H(1,s)H(0,s) = H(1,s) for all ss.

Theorem3.5Deformation invariance

If ff is holomorphic on a domain DD and γ0,γ1\gamma_0, \gamma_1 are homotopic closed curves in DD, then

γ0f(z)dz=γ1f(z)dz.\oint_{\gamma_0} f(z)\,dz = \oint_{\gamma_1} f(z)\,dz.

ExampleDeforming around a singularity

Let f(z)=1/zf(z) = 1/z and let γR\gamma_R be the circle z=R|z| = R for any R>0R > 0. All these circles are homotopic in C{0}\mathbb{C} \setminus \{0\}, so

z=Rdzz=2πi\oint_{|z|=R} \frac{dz}{z} = 2\pi i

for all R>0R > 0. However, a circle not enclosing the origin is homotopic to a point, giving integral zero.


Winding Number

RemarkWinding number

For a closed curve γ\gamma in C{z0}\mathbb{C} \setminus \{z_0\}, the winding number (or index) of γ\gamma around z0z_0 is

n(γ,z0)=12πiγdzzz0.n(\gamma, z_0) = \frac{1}{2\pi i} \oint_\gamma \frac{dz}{z - z_0}.

This is always an integer and counts the number of times γ\gamma winds around z0z_0 (with sign indicating direction). The winding number is a homotopy invariant and plays a central role in the general form of Cauchy's integral formula.