Fundamental Theorem of Algebra
The fundamental theorem of algebra states that every non-constant polynomial with complex coefficients has at least one complex root. This remarkable result shows that is algebraically closed.
Statement
Every non-constant polynomial with complex coefficients and has at least one root in . That is, there exists such that .
By induction, every polynomial of degree factors completely into linear factors:
where (counted with multiplicity). This is why is called algebraically closed: every polynomial equation has all its roots within .
Proof Strategy
There are many proofs of the fundamental theorem, using tools from:
- Complex analysis: If has no zeros, then is entire and bounded (since as ). By Liouville's theorem, is constant, a contradiction.
- Topology: Using the fact that induces a nontrivial map on fundamental groups if has no zeros.
- Real analysis: Showing that attains a minimum at some , and proving that this minimum must be zero.
The complex-analytic proof is elegant but requires Liouville's theorem. A more elementary proof is given in Proof 1.
Examples and Applications
Every quadratic (with ) has two roots (counted with multiplicity):
The discriminant can be any complex number. Unlike in real analysis, there is no distinction between "positive" and "negative" discriminants — every quadratic has two complex roots.
The polynomial factors as
where are the -th roots of unity. This is a direct application of the fundamental theorem.
has no real roots, but has two complex roots: and . Thus
More generally, every real polynomial of odd degree has at least one real root (by the intermediate value theorem), but polynomials of even degree need not have real roots.
Historical Remark
The fundamental theorem was first stated by d'Alembert (1746) and proved rigorously by Gauss (1799), who gave four different proofs over his lifetime. The name "fundamental theorem of algebra" is somewhat misleading: all rigorous proofs use tools from analysis or topology, not just algebra. A purely algebraic proof is impossible in first-order logic, as shown by model theory.
The theorem is fundamental because it guarantees that polynomial equations always have solutions in , making the "correct" number system for algebra.
Relation to Other Results
The most elegant proof uses Liouville's theorem: every bounded entire function is constant. If is a non-constant polynomial with no zeros, then is entire (holomorphic on all of ). Since as , we have , so is bounded. By Liouville, is constant, implying is constant — a contradiction.
This proof is given in detail in Liouville's theorem.
Summary
- Every non-constant polynomial has at least one complex root.
- As a consequence, factors completely into linear factors over .
- is algebraically closed: polynomial equations are always solvable.
- The theorem requires tools beyond pure algebra — complex analysis provides the most elegant proofs.
- The fundamental theorem underlies much of complex analysis, including the theory of entire functions and meromorphic functions.