ConceptComplete

Entire Functions

Entire functions are holomorphic on all of C\mathbb{C}. Their global theory, including growth estimates, factorization, and value distribution, reveals deep structural properties.


Growth and Order

Definition9.1Order of an entire function

The order of an entire function ff is

ρ=lim sup⁑rβ†’βˆžlog⁑log⁑M(r)log⁑r\rho = \limsup_{r\to\infty}\frac{\log\log M(r)}{\log r}

where M(r)=max⁑∣z∣=r∣f(z)∣M(r) = \max_{|z|=r}|f(z)|. The type (for finite order ρ\rho) is Οƒ=lim sup⁑rβ†’βˆžlog⁑M(r)rρ\sigma = \limsup_{r\to\infty} \frac{\log M(r)}{r^\rho}.

ExampleOrders of common entire functions
  • Polynomials: ρ=0\rho = 0.
  • eze^z: M(r)=erM(r) = e^r, so ρ=1\rho = 1 and Οƒ=1\sigma = 1 (normal type).
  • ez2e^{z^2}: M(r)=er2M(r) = e^{r^2}, so ρ=2\rho = 2 and Οƒ=1\sigma = 1.
  • cos⁑z\cos z: M(r)∼er/2M(r) \sim e^r/2, so ρ=1\rho = 1 and Οƒ=1\sigma = 1.
  • sin⁑(z)/z\sin(\sqrt{z})/\sqrt{z}: ρ=1/2\rho = 1/2.

Weierstrass Factorization

Definition9.2Elementary factors

The elementary factor of order pp is

Ep(z)=(1βˆ’z)exp⁑(z+z22+β‹―+zpp).E_p(z) = (1-z)\exp\left(z + \frac{z^2}{2} + \cdots + \frac{z^p}{p}\right).

For p=0p = 0: E0(z)=1βˆ’zE_0(z) = 1 - z. The exponential factor ensures convergence of infinite products.

Theorem9.1Weierstrass factorization theorem

Let ff be entire with zeros {an}\{a_n\} (repeated by multiplicity), f(0)β‰ 0f(0) \neq 0. There exist integers {pn}\{p_n\} and an entire function gg such that

f(z)=eg(z)∏n=1∞Epn(z/an).f(z) = e^{g(z)}\prod_{n=1}^{\infty}E_{p_n}(z/a_n).

If the zeros satisfy βˆ‘βˆ£anβˆ£βˆ’(p+1)<∞\sum |a_n|^{-(p+1)} < \infty for some pp, we can take all pn=pp_n = p, and the product converges. The smallest such pp is the genus of the product.

ExampleFactorization of $\sin(\pi z)$

The zeros of sin⁑(Ο€z)\sin(\pi z) are {n:n∈Z}\{n : n \in \mathbb{Z}\}. Since βˆ‘1/∣n∣2<∞\sum 1/|n|^2 < \infty, we can use p=1p = 1:

sin⁑(Ο€z)=Ο€z∏n=1∞(1βˆ’z2n2)=Ο€z∏n=1∞E1(z/n)E1(βˆ’z/n).\sin(\pi z) = \pi z \prod_{n=1}^{\infty}\left(1 - \frac{z^2}{n^2}\right) = \pi z \prod_{n=1}^{\infty}E_1(z/n)E_1(-z/n).

Setting z=1/2z = 1/2: 1=Ο€2∏n=1∞(1βˆ’1/(4n2))1 = \frac{\pi}{2}\prod_{n=1}^\infty(1-1/(4n^2)), yielding Wallis's product Ο€2=∏n=1∞4n24n2βˆ’1\frac{\pi}{2} = \prod_{n=1}^\infty\frac{4n^2}{4n^2-1}.


The Hadamard Factorization Theorem

Theorem9.2Hadamard factorization theorem

If ff is entire of finite order ρ\rho with zeros {an}\{a_n\} and ff vanishes to order mm at the origin, then

f(z)=zmeQ(z)∏nEp(z/an)f(z) = z^m e^{Q(z)}\prod_{n} E_p(z/a_n)

where QQ is a polynomial of degree at most ρ\rho and p=βŒŠΟβŒ‹p = \lfloor\rho\rfloor.

ExampleHadamard factorization of $\cos(\pi z)$

cos⁑(Ο€z)\cos(\pi z) has order 11, zeros at z=n+1/2z = n + 1/2 for n∈Zn \in \mathbb{Z}. By Hadamard:

cos⁑(Ο€z)=eaz+b∏n=βˆ’βˆžβˆž(1βˆ’zn+1/2)ez/(n+1/2)=∏n=0∞(1βˆ’4z2(2n+1)2).\cos(\pi z) = e^{az+b}\prod_{n=-\infty}^{\infty}\left(1 - \frac{z}{n+1/2}\right)e^{z/(n+1/2)} = \prod_{n=0}^{\infty}\left(1 - \frac{4z^2}{(2n+1)^2}\right).


Summary

RemarkStructure of entire functions

The theory of entire functions reveals that:

  1. Every entire function is determined (up to an exponential factor) by its zeros.
  2. The growth rate constrains how many zeros the function can have (genus ≀\leq order).
  3. The Hadamard factorization provides a canonical representation for functions of finite order.