ConceptComplete

Dedekind Domains and Factorization - Key Properties

Dedekind domains possess remarkable properties that distinguish them from general integral domains and enable ideal-theoretic arithmetic.

DefinitionIdeal Norm

For a nonzero ideal II in OK\mathcal{O}_K, the norm is defined as N(I)=OK/IN(I) = |\mathcal{O}_K / I| the cardinality of the quotient ring. For principal ideals, N((α))=NK/Q(α)N((\alpha)) = |N_{K/\mathbb{Q}}(\alpha)|.

The norm is multiplicative: N(IJ)=N(I)N(J)N(IJ) = N(I)N(J). For prime ideals p\mathfrak{p} lying over a rational prime pp, we have N(p)=pfN(\mathfrak{p}) = p^f where ff is the inertia degree.

ExampleComputing Ideal Norms

In Z[i]\mathbb{Z}[i], the ideal p=(2+i)\mathfrak{p} = (2+i) has norm N(p)=Z[i]/(2+i)=N(2+i)=4(1)=5N(\mathfrak{p}) = |\mathbb{Z}[i]/(2+i)| = |N(2+i)| = |4 - (-1)| = 5

For the ideal (1i)(1-i) in Z[i]\mathbb{Z}[i], we compute N((1i))=N(1i)=1(1)=2N((1-i)) = |N(1-i)| = |1 - (-1)| = 2 Note that (2)=(1i)2(2) = (1-i)^2 in Z[i]\mathbb{Z}[i], consistent with N((2))=4=22N((2)) = 4 = 2^2.

DefinitionSplitting of Primes

Let p\mathfrak{p} be a prime ideal of OK\mathcal{O}_K lying above a rational prime pp (meaning pZ=(p)\mathfrak{p} \cap \mathbb{Z} = (p)). The factorization of (p)(p) in OK\mathcal{O}_K is (p)=p1e1pgeg(p) = \mathfrak{p}_1^{e_1} \cdots \mathfrak{p}_g^{e_g}

where:

  • eie_i is the ramification index of pi\mathfrak{p}_i
  • fif_i is the inertia degree (residue field degree) of pi\mathfrak{p}_i
  • These satisfy i=1geifi=n=[K:Q]\sum_{i=1}^g e_i f_i = n = [K : \mathbb{Q}]

A prime pp splits completely if ei=fi=1e_i = f_i = 1 for all ii (so g=ng = n). It ramifies if some ei>1e_i > 1, and is inert if g=1g = 1 and e1=1,f1=ne_1 = 1, f_1 = n.

ExampleSplitting in Quadratic Fields

For K=Q(d)K = \mathbb{Q}(\sqrt{d}) and prime p2dp \nmid 2d:

  • pp splits: (p)=ppˉ(p) = \mathfrak{p}\bar{\mathfrak{p}} if (dp)=1\left(\frac{d}{p}\right) = 1
  • pp is inert: (p)(p) remains prime if (dp)=1\left(\frac{d}{p}\right) = -1
  • pp ramifies: (p)=p2(p) = \mathfrak{p}^2 if pdp | d

For K=Q(i)K = \mathbb{Q}(i) and p=5p = 5: Since (15)=1\left(\frac{-1}{5}\right) = 1, we have (5)=(2+i)(2i)(5) = (2+i)(2-i).

Remark

The Chinese Remainder Theorem holds in Dedekind domains: if I1,,InI_1, \ldots, I_n are pairwise coprime ideals (meaning Ii+Ij=RI_i + I_j = R for iji \neq j), then OK/(I1In)OK/I1××OK/In\mathcal{O}_K / (I_1 \cdots I_n) \cong \mathcal{O}_K/I_1 \times \cdots \times \mathcal{O}_K/I_n This isomorphism is crucial for computing with ideals and solving congruences.

DefinitionInvertibility

A fractional ideal II is invertible if there exists a fractional ideal JJ such that IJ=RIJ = R. In a Dedekind domain, every nonzero fractional ideal is invertible.

The group of fractional ideals modulo principal ideals is the ideal class group Cl(K)\text{Cl}(K), measuring the failure of unique factorization.

The class number hK=Cl(K)h_K = |\text{Cl}(K)| is finite for number fields, a deep result combining geometry of numbers and analysis. When hK=1h_K = 1, the ring OK\mathcal{O}_K is a principal ideal domain (PID), hence a unique factorization domain (UFD).