ProofComplete

Proof of the Upcrossing Inequality

The upcrossing inequality is the key technical tool in proving Doob's martingale convergence theorem. It bounds the expected number of times a submartingale crosses upward through an interval.


Statement

Theorem3.1Doob's upcrossing inequality

Let (Xn)(X_n) be a submartingale and Un(a,b)U_n(a, b) the number of upcrossings of [a,b][a, b] by (X0,X1,…,Xn)(X_0, X_1, \ldots, X_n). Then:

E[Un(a,b)]≀E[(Xnβˆ’a)+]bβˆ’a.\mathbb{E}[U_n(a, b)] \leq \frac{\mathbb{E}[(X_n - a)^+]}{b - a}.


Proof

Step 1: Define the stopped process Yk=(Xkβˆ’a)+Y_k = (X_k - a)^+ (shift so the interval is [0,bβˆ’a][0, b-a]).

Step 2: Track upcrossings using a betting strategy. Let Ξ²0,Ξ²1,…\beta_0, \beta_1, \ldots be the starts of upcrossings (below 00) and Ξ±1,Ξ±2,…\alpha_1, \alpha_2, \ldots the completions (above bβˆ’ab-a). The total gain from upcrossings is at least (bβˆ’a)Un(a,b)(b-a) U_n(a,b).

Step 3: By the submartingale property and the optional stopping theorem for the martingale transform (betting 11 during upcrossings, 00 otherwise):

(bβˆ’a)Un(a,b)≀E[Yn]=E[(Xnβˆ’a)+].(b-a) U_n(a,b) \leq \mathbb{E}[Y_n] = \mathbb{E}[(X_n - a)^+].

Rearranging gives the result.


Consequence

If E[(Xnβˆ’a)+]≀C\mathbb{E}[(X_n - a)^+] \leq C for all nn, then E[U∞(a,b)]≀C/(bβˆ’a)<∞\mathbb{E}[U_\infty(a, b)] \leq C/(b-a) < \infty, so U∞(a,b)<∞U_\infty(a, b) < \infty a.s. This means the process crosses [a,b][a,b] finitely many times, implying convergence.