ConceptComplete

Types of Discontinuities

Not all functions are continuous. When a function fails to be continuous at a point, we classify the type of discontinuity. The three main types are: removable discontinuities (where a limit exists but doesn't match the function value), jump discontinuities (where left and right limits exist but differ), and essential discontinuities (where limits fail to exist). Understanding discontinuities is crucial for integration theory and Fourier analysis.


Definitions

Definition4.1One-sided limits

Let ff be defined on an interval containing cc (except possibly at cc itself). The right-hand limit of ff at cc is

limxc+f(x)=L\lim_{x \to c^+} f(x) = L

if for every ϵ>0\epsilon > 0, there exists δ>0\delta > 0 such that 0<xc<δ    f(x)L<ϵ0 < x - c < \delta \implies |f(x) - L| < \epsilon.

Similarly, the left-hand limit is limxcf(x)\lim_{x \to c^-} f(x).

RemarkTwo-sided limit

The (two-sided) limit limxcf(x)=L\lim_{x \to c} f(x) = L exists if and only if limxc+f(x)=limxcf(x)=L\lim_{x \to c^+} f(x) = \lim_{x \to c^-} f(x) = L.


Types of discontinuities

Definition4.2Removable discontinuity

ff has a removable discontinuity at cc if limxcf(x)\lim_{x \to c} f(x) exists but either f(c)f(c) is undefined or limxcf(x)f(c)\lim_{x \to c} f(x) \neq f(c).

ExampleRemovable discontinuity

Let f(x)=sin(x)xf(x) = \frac{\sin(x)}{x} for x0x \neq 0 and f(0)=0f(0) = 0. Then limx0f(x)=1f(0)\lim_{x \to 0} f(x) = 1 \neq f(0), so ff has a removable discontinuity at 00. We can "remove" it by redefining f(0)=1f(0) = 1.

Definition4.3Jump discontinuity

ff has a jump discontinuity at cc if limxc+f(x)\lim_{x \to c^+} f(x) and limxcf(x)\lim_{x \to c^-} f(x) both exist but are not equal.

ExampleJump discontinuity

The Heaviside function

H(x)={0x<0,1x0H(x) = \begin{cases} 0 & x < 0, \\ 1 & x \geq 0 \end{cases}

has a jump discontinuity at x=0x = 0: limx0H(x)=0\lim_{x \to 0^-} H(x) = 0 and limx0+H(x)=1\lim_{x \to 0^+} H(x) = 1. The jump size is 10=11 - 0 = 1.

Definition4.4Essential discontinuity

ff has an essential discontinuity (or infinite discontinuity) at cc if at least one of the one-sided limits fails to exist (or is infinite).

ExampleEssential discontinuity

Let f(x)=sin(1/x)f(x) = \sin(1/x) for x0x \neq 0. As x0x \to 0, 1/x±1/x \to \pm\infty and sin(1/x)\sin(1/x) oscillates between 1-1 and 11 infinitely often. Thus limx0sin(1/x)\lim_{x \to 0} \sin(1/x) does not exist — ff has an essential discontinuity at 00.

ExampleInfinite discontinuity

f(x)=1/xf(x) = 1/x at x=0x = 0 has an essential discontinuity: limx0+f(x)=+\lim_{x \to 0^+} f(x) = +\infty and limx0f(x)=\lim_{x \to 0^-} f(x) = -\infty. Neither one-sided limit is finite.


Monotone functions and discontinuities

Theorem4.1Monotone functions have at most countably many discontinuities

If f:[a,b]Rf : [a, b] \to \mathbb{R} is monotone, then the set of discontinuities of ff is at most countable.

RemarkProof sketch

For a monotone increasing ff, each discontinuity is a jump discontinuity. At each jump, associate a rational number in the "jump interval." Since the rationals are countable, there are at most countably many jumps.

ExampleStaircase function

Define f(x)=xf(x) = \lfloor x \rfloor (the greatest integer x\leq x). Then ff is increasing and has jump discontinuities at every integer, with limxnf(x)=n1\lim_{x \to n^-} f(x) = n - 1 and limxn+f(x)=n\lim_{x \to n^+} f(x) = n. There are countably many discontinuities.


Summary

Discontinuities are classified into three types:

  • Removable: limit exists, can be "fixed" by redefining the function.
  • Jump: one-sided limits exist but differ.
  • Essential: at least one limit fails to exist.
  • Monotone functions have at most countably many discontinuities (all jumps).

See Intermediate Value Theorem and Riemann Integration for how continuity and discontinuities affect analysis.