ConceptComplete

Ordinary Points and Power Series Solutions

Power series methods provide systematic techniques for solving linear ODEs near ordinary and singular points, yielding solutions as convergent infinite series.


Analytic ODEs and Ordinary Points

Definition9.1Ordinary and singular points

Consider the second-order linear ODE y+P(x)y+Q(x)y=0y'' + P(x)y' + Q(x)y = 0. A point x0x_0 is an ordinary point if both P(x)P(x) and Q(x)Q(x) are analytic (have convergent power series expansions) at x0x_0. Otherwise, x0x_0 is a singular point.

Equivalently, for the standard form a2(x)y+a1(x)y+a0(x)y=0a_2(x)y'' + a_1(x)y' + a_0(x)y = 0 with analytic coefficients, x0x_0 is ordinary if a2(x0)0a_2(x_0) \neq 0, and singular if a2(x0)=0a_2(x_0) = 0.

Theorem9.1Existence of power series solutions at ordinary points

If x0x_0 is an ordinary point of y+P(x)y+Q(x)y=0y'' + P(x)y' + Q(x)y = 0, then there exist two linearly independent solutions of the form:

y(x)=n=0an(xx0)n,y(x) = \sum_{n=0}^{\infty} a_n (x - x_0)^n,

and the radius of convergence of each series is at least the distance from x0x_0 to the nearest singular point (in C\mathbb{C}).


The Recurrence Method

ExampleAiry equation

The Airy equation yxy=0y'' - xy = 0 has x0=0x_0 = 0 as an ordinary point (no finite singular points, so R=R = \infty). Substituting y=anxny = \sum a_n x^n:

n=2n(n1)anxn2n=0anxn+1=0.\sum_{n=2}^{\infty} n(n-1)a_n x^{n-2} - \sum_{n=0}^{\infty} a_n x^{n+1} = 0.

Re-indexing: n=0(n+2)(n+1)an+2xn=n=1an1xn\sum_{n=0}^{\infty}(n+2)(n+1)a_{n+2}x^n = \sum_{n=1}^{\infty}a_{n-1}x^n. So 2a2=02a_2 = 0 (hence a2=0a_2 = 0) and for n1n \geq 1:

an+2=an1(n+2)(n+1).a_{n+2} = \frac{a_{n-1}}{(n+2)(n+1)}.

With a0a_0 and a1a_1 free, the two linearly independent solutions are the Airy functions Ai(x)\mathrm{Ai}(x) and Bi(x)\mathrm{Bi}(x), both entire functions.

ExampleHermite equation

y2xy+2ny=0y'' - 2xy' + 2ny = 0 (nn a parameter). At x0=0x_0 = 0 (ordinary point), substitute y=akxky = \sum a_k x^k:

ak+2=2(kn)(k+2)(k+1)ak.a_{k+2} = \frac{2(k - n)}{(k+2)(k+1)} a_k.

When nn is a non-negative integer, the series terminates, yielding the Hermite polynomials Hn(x)H_n(x). For n=0n = 0: H0=1H_0 = 1. For n=1n = 1: H1=2xH_1 = 2x. For n=2n = 2: H2=4x22H_2 = 4x^2 - 2.


Convergence Analysis

RemarkDetermining the radius of convergence

The radius of convergence RR is at least min(RP,RQ)\min(R_P, R_Q), where RPR_P and RQR_Q are the radii of convergence of P(x)P(x) and Q(x)Q(x) about x0x_0. This is equivalent to the distance from x0x_0 to the nearest singularity of PP or QQ in the complex plane.

For example, (1+x2)y+y=0(1+x^2)y'' + y = 0 has P=0P = 0, Q=1/(1+x2)Q = 1/(1+x^2), which is singular at x=±ix = \pm i. Series about x0=0x_0 = 0 converge for x<1|x| < 1.

This illustrates a key insight: complex singularities limit the radius of convergence of real power series solutions.

RemarkPractical computation

To find the first NN terms of a power series solution:

  1. Write y=n=0Nan(xx0)ny = \sum_{n=0}^{N} a_n(x-x_0)^n.
  2. Substitute into the ODE and collect powers.
  3. Set each coefficient to zero to obtain a recurrence relation for {an}\{a_n\}.
  4. Express ana_n in terms of a0a_0 (and a1a_1 for second-order).
  5. The two free constants a0a_0, a1a_1 correspond to the two linearly independent solutions.