ConceptComplete

Lp Spaces - Key Properties

The LpL^p spaces satisfy fundamental inequalities that establish their norm properties and enable their use in analysis. These inequalities are essential tools throughout mathematics.

TheoremHolder's Inequality

Let 1p,q1 \leq p, q \leq \infty with 1p+1q=1\frac{1}{p} + \frac{1}{q} = 1 (we say pp and qq are conjugate exponents). If fLpf \in L^p and gLqg \in L^q, then fgL1fg \in L^1 and: Xfgdμfpgq\int_X |fg| \, d\mu \leq \|f\|_p \|g\|_q

For p=q=2p = q = 2, this reduces to the Cauchy-Schwarz inequality: Xfgdμf2g2\int_X |fg| \, d\mu \leq \|f\|_2 \|g\|_2

TheoremMinkowski's Inequality

For 1p1 \leq p \leq \infty, if f,gLpf, g \in L^p, then f+gLpf + g \in L^p and: f+gpfp+gp\|f + g\|_p \leq \|f\|_p + \|g\|_p

This is the triangle inequality for the LpL^p norm, establishing that p\|\cdot\|_p is indeed a norm.

These two inequalities are cornerstones of LpL^p theory. Holder's inequality provides a way to bound products, while Minkowski's inequality establishes the norm structure.

ExampleApplications
  1. Bounding integrals: To estimate 01x1/3sin(x)dx\int_0^1 x^{-1/3} \sin(x) \, dx, note that x1/3L3/2([0,1])x^{-1/3} \in L^{3/2}([0,1]) and sin(x)L3([0,1])\sin(x) \in L^3([0,1]). By Holder's inequality with p=3/2p = 3/2, q=3q = 3: 01x1/3sin(x)dxx1/33/2sin3<\left|\int_0^1 x^{-1/3} \sin(x) \, dx\right| \leq \|x^{-1/3}\|_{3/2} \|\sin\|_3 < \infty

  2. L2L^2 orthogonality: In L2L^2, if f,g=fg=0\langle f, g \rangle = \int fg = 0, then by Pythagorean theorem (derived from Minkowski): f+g22=f22+g22\|f + g\|_2^2 = \|f\|_2^2 + \|g\|_2^2

Remark

Additional important properties:

  1. Interpolation: For 1p0<p<p11 \leq p_0 < p < p_1 \leq \infty and θ(0,1)\theta \in (0, 1) with 1p=1θp0+θp1\frac{1}{p} = \frac{1-\theta}{p_0} + \frac{\theta}{p_1}, if fLp0Lp1f \in L^{p_0} \cap L^{p_1}, then fLpf \in L^p and: fpfp01θfp1θ\|f\|_p \leq \|f\|_{p_0}^{1-\theta} \|f\|_{p_1}^{\theta}

  2. Completeness (Riesz-Fischer): LpL^p is complete for all 1p1 \leq p \leq \infty. If {fn}\{f_n\} is Cauchy in LpL^p, then there exists fLpf \in L^p with fnfp0\|f_n - f\|_p \to 0.

  3. Dense subsets: On Rn\mathbb{R}^n, continuous functions with compact support are dense in LpL^p for 1p<1 \leq p < \infty.

  4. Separability: Lp(Rn)L^p(\mathbb{R}^n) is separable for 1p<1 \leq p < \infty, but LL^\infty is not separable.