Normed and Banach Spaces - Key Proof
We present a detailed proof of the completion theorem, showing that every normed space can be embedded isometrically into a Banach space as a dense subspace.
Let be a normed space. Then there exists a Banach space and an isometric linear embedding such that is dense in . Moreover, this completion is unique up to isometric isomorphism.
Construction: Let be the set of all Cauchy sequences in . Define an equivalence relation on by
Let be the quotient space. For a Cauchy sequence , denote its equivalence class by .
Vector Space Structure: Define operations on by
These are well-defined (independent of representatives) and make a vector space over .
Norm: For a Cauchy sequence , the sequence is Cauchy in , hence convergent. Define
This is well-defined and defines a norm on .
Embedding: Define by (the constant sequence). Then:
- is linear:
- is isometric:
- is dense: Every is the limit of
Completeness: Let be a Cauchy sequence in where . For each , choose such that . Then is Cauchy in , so is the limit of .
Uniqueness: If and are two completions, the denseness and continuity force a unique isometric isomorphism with .
-
Polynomials to Continuous Functions: The space of polynomials on with supremum norm completes to
-
Rational Numbers: The normed space completes to
-
Step Functions: Simple functions on a measure space complete to spaces
The completion theorem is a powerful existence result that allows us to work in complete spaces even when starting from incomplete ones. In practice, many important function spaces arise naturally as completions of simpler spaces.
This construction parallels the completion of metric spaces but preserves the additional linear and norm structures, making it a cornerstone of functional analysis.