ConceptComplete

Change of Variables in Multiple Integrals

Coordinate transformations simplify the evaluation of multiple integrals by choosing coordinates adapted to the geometry of the domain, with the Jacobian determinant accounting for the distortion of area or volume.


The Change of Variables Formula

Definition

A coordinate transformation (or change of variables) is a differentiable bijection T:GDT : G \to D from a region GG in (u,v)(u,v)-space to a region DD in (x,y)(x,y)-space, given by x=x(u,v)x = x(u,v), y=y(u,v)y = y(u,v). The Jacobian of TT is (x,y)(u,v)=det(xuxvyuyv)\frac{\partial(x,y)}{\partial(u,v)} = \det \begin{pmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{pmatrix} Its absolute value (x,y)(u,v)\left|\frac{\partial(x,y)}{\partial(u,v)}\right| measures the local area scaling factor of the transformation.

Theorem9.2Change of Variables (Double Integral)

If T:GDT : G \to D is a C1C^1 bijection with (x,y)(u,v)0\frac{\partial(x,y)}{\partial(u,v)} \neq 0 on GG, then Df(x,y)dxdy=Gf(x(u,v),y(u,v))(x,y)(u,v)dudv\iint_D f(x,y)\,dx\,dy = \iint_G f(x(u,v), y(u,v)) \left|\frac{\partial(x,y)}{\partial(u,v)}\right| du\,dv


Standard Coordinate Systems

ExamplePolar, cylindrical, and spherical coordinates

Polar (x=rcosθx = r\cos\theta, y=rsinθy = r\sin\theta): Jacobian =r= r Df(x,y)dA=θ1θ2r1(θ)r2(θ)f(rcosθ,rsinθ)rdrdθ\iint_D f(x,y)\,dA = \int_{\theta_1}^{\theta_2}\int_{r_1(\theta)}^{r_2(\theta)} f(r\cos\theta, r\sin\theta)\, r\,dr\,d\theta

Cylindrical (x=rcosθx = r\cos\theta, y=rsinθy = r\sin\theta, z=zz = z): Jacobian =r= r

Spherical (x=ρsinϕcosθx = \rho\sin\phi\cos\theta, y=ρsinϕsinθy = \rho\sin\phi\sin\theta, z=ρcosϕz = \rho\cos\phi): Jacobian =ρ2sinϕ= \rho^2\sin\phi EfdV= ⁣ ⁣ ⁣ ⁣f(ρ,ϕ,θ)ρ2sinϕdρdϕdθ\iiint_E f\,dV = \int\!\!\int\!\!\int f(\rho,\phi,\theta)\,\rho^2 \sin\phi\,d\rho\,d\phi\,d\theta

ExampleArea of a disk using polar coordinates

A=x2+y2R2dA=02π0Rrdrdθ=02πR22dθ=πR2A = \iint_{x^2+y^2 \leq R^2} dA = \int_0^{2\pi}\int_0^R r\,dr\,d\theta = \int_0^{2\pi} \frac{R^2}{2}\,d\theta = \pi R^2


RemarkChoosing the right coordinates

The key to effective use of coordinate transformations is matching the coordinates to the symmetry of the domain. Circular domains suggest polar coordinates, cylindrical domains suggest cylindrical coordinates, and spherical domains suggest spherical coordinates. In general, choose coordinates in which the boundary of the domain takes a simple form.