ConceptComplete

Operations on Power Series

Power series can be added, multiplied, differentiated, and integrated term by term within their interval of convergence, making them a powerful computational tool.


Term-by-Term Operations

Definition

Given two power series f(x)=anxnf(x) = \sum a_n x^n and g(x)=bnxng(x) = \sum b_n x^n with radii RfR_f and RgR_g respectively:

  • Sum: (f+g)(x)=(an+bn)xn(f + g)(x) = \sum (a_n + b_n) x^n with radius min(Rf,Rg)\geq \min(R_f, R_g)
  • Cauchy product: (fg)(x)=n=0cnxn(f \cdot g)(x) = \sum_{n=0}^\infty c_n x^n where cn=k=0nakbnkc_n = \sum_{k=0}^n a_k b_{n-k} with radius min(Rf,Rg)\geq \min(R_f, R_g)
  • Composition: f(g(x))f(g(x)) is a power series when g(x)<Rf|g(x)| < R_f
Theorem7.3Term-by-Term Differentiation and Integration

If f(x)=n=0cnxnf(x) = \sum_{n=0}^\infty c_n x^n has radius of convergence R>0R > 0, then:

  1. ff is differentiable on (R,R)(-R, R) and f(x)=n=1ncnxn1f'(x) = \sum_{n=1}^\infty n c_n x^{n-1}
  2. ff is integrable and f(x)dx=C+n=0cnn+1xn+1\int f(x)\,dx = C + \sum_{n=0}^\infty \frac{c_n}{n+1} x^{n+1}
  3. Both derived series have the same radius of convergence RR.

Applications

ExampleDeriving new series from known ones

Starting from 11x=xn\frac{1}{1-x} = \sum x^n:

  • Differentiate: 1(1x)2=n=1nxn1=n=0(n+1)xn\frac{1}{(1-x)^2} = \sum_{n=1}^\infty n x^{n-1} = \sum_{n=0}^\infty (n+1)x^n
  • Integrate: ln(1x)=n=0xn+1n+1=n=1xnn-\ln(1-x) = \sum_{n=0}^\infty \frac{x^{n+1}}{n+1} = \sum_{n=1}^\infty \frac{x^n}{n}
  • Substitute xx2x \to -x^2: 11+x2=n=0(1)nx2n\frac{1}{1+x^2} = \sum_{n=0}^\infty (-1)^n x^{2n}
  • Integrate the last: arctanx=n=0(1)nx2n+12n+1\arctan x = \sum_{n=0}^\infty \frac{(-1)^n x^{2n+1}}{2n+1}

Setting x=1x = 1 in the arctangent series gives Leibniz's formula: π4=113+1517+\frac{\pi}{4} = 1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \cdots


Uniqueness

RemarkIdentity theorem for power series

If two power series an(xa)n\sum a_n (x-a)^n and bn(xa)n\sum b_n (x-a)^n agree on an open interval containing aa, then an=bna_n = b_n for all nn. This identity theorem means the power series representation of a function (when it exists) is unique. It follows that the coefficients must be the Taylor coefficients: cn=f(n)(a)/n!c_n = f^{(n)}(a)/n!.

The algebra of power series, combined with term-by-term calculus, provides an efficient framework for computing limits, integrals, and solutions to differential equations that would be difficult to handle by other methods.