ConceptComplete

Sequences and Series - Core Definitions

Sequences and series extend calculus to discrete settings, providing tools for approximation, convergence analysis, and representation of functions. Understanding limits of sequences is fundamental to infinite series and power series.

DefinitionSequence

A sequence is a function whose domain is the set of positive integers. We denote the sequence as {an}n=1\{a_n\}_{n=1}^\infty or simply {an}\{a_n\}, where ana_n is the nn-th term.

Examples:

  • {n2}=1,4,9,16,25,\{n^2\} = 1, 4, 9, 16, 25, \ldots
  • {1n}=1,12,13,14,\left\{\frac{1}{n}\right\} = 1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \ldots
  • {(1)n}=1,1,1,1,1,\{(-1)^n\} = -1, 1, -1, 1, -1, \ldots
DefinitionLimit of a Sequence

We say that {an}\{a_n\} converges to LL, written limnan=L\lim_{n \to \infty} a_n = L, if for every ϵ>0\epsilon > 0, there exists NN such that n>N    anL<ϵn > N \implies |a_n - L| < \epsilon

If no such LL exists, the sequence diverges.

ExampleConvergent Sequences
  1. limn1n=0\lim_{n \to \infty} \frac{1}{n} = 0: The terms get arbitrarily close to 0
  2. limnn+1n=limn(1+1n)=1\lim_{n \to \infty} \frac{n+1}{n} = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right) = 1
  3. limnn22n2+1=limn12+1/n2=12\lim_{n \to \infty} \frac{n^2}{2n^2 + 1} = \lim_{n \to \infty} \frac{1}{2 + 1/n^2} = \frac{1}{2}
ExampleDivergent Sequences
  1. {n}\{n\} diverges to infinity
  2. {(1)n}\{(-1)^n\} oscillates between 1-1 and 11, so has no limit
  3. {(1)nn}\{(-1)^n n\} oscillates with unbounded magnitude
TheoremLimit Laws for Sequences

If limnan=A\lim_{n \to \infty} a_n = A and limnbn=B\lim_{n \to \infty} b_n = B, then:

  1. limn(an+bn)=A+B\lim_{n \to \infty} (a_n + b_n) = A + B
  2. limn(can)=cA\lim_{n \to \infty} (ca_n) = cA for any constant cc
  3. limn(anbn)=AB\lim_{n \to \infty} (a_n b_n) = AB
  4. limnanbn=AB\lim_{n \to \infty} \frac{a_n}{b_n} = \frac{A}{B} if B0B \neq 0
  5. limn(an)p=Ap\lim_{n \to \infty} (a_n)^p = A^p if p>0p > 0 and an>0a_n > 0
TheoremSqueeze Theorem for Sequences

If anbncna_n \leq b_n \leq c_n for all nn beyond some point, and limnan=limncn=L\lim_{n \to \infty} a_n = \lim_{n \to \infty} c_n = L, then limnbn=L\lim_{n \to \infty} b_n = L

ExampleUsing the Squeeze Theorem

Find limnsinnn\lim_{n \to \infty} \frac{\sin n}{n}.

Since 1sinn1-1 \leq \sin n \leq 1 for all nn: 1nsinnn1n-\frac{1}{n} \leq \frac{\sin n}{n} \leq \frac{1}{n}

Since limn1n=0\lim_{n \to \infty} \frac{1}{n} = 0 and limn1n=0\lim_{n \to \infty} -\frac{1}{n} = 0, by the Squeeze Theorem: limnsinnn=0\lim_{n \to \infty} \frac{\sin n}{n} = 0

DefinitionMonotonic Sequences

A sequence {an}\{a_n\} is:

  • Increasing if anan+1a_n \leq a_{n+1} for all nn
  • Decreasing if anan+1a_n \geq a_{n+1} for all nn
  • Monotonic if it is either increasing or decreasing
TheoremMonotone Convergence Theorem

Every bounded monotonic sequence converges.

Specifically:

  • If {an}\{a_n\} is increasing and bounded above, it converges to sup{an}\sup\{a_n\}
  • If {an}\{a_n\} is decreasing and bounded below, it converges to inf{an}\inf\{a_n\}
ExampleApplication of Monotone Convergence

Consider an=(1+1n)na_n = \left(1 + \frac{1}{n}\right)^n.

This sequence is increasing and bounded above by 3 (can be shown using binomial theorem). By the Monotone Convergence Theorem, it converges. The limit is the famous constant: limn(1+1n)n=e2.71828\lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n = e \approx 2.71828

Remark

Connection to functions: If f(x)f(x) is defined for x1x \geq 1 and an=f(n)a_n = f(n), then limnan=limxf(x)\lim_{n \to \infty} a_n = \lim_{x \to \infty} f(x) when both limits exist. This allows us to use L'Hôpital's Rule and other continuous function techniques for sequences.

Sequences provide the foundation for understanding series, which are infinite sums of sequence terms.