ConceptComplete

Limits and Continuity - Examples and Constructions

Infinite limits and limits at infinity describe the behavior of functions as they approach unbounded values or as their arguments grow without bound. These concepts are essential for understanding asymptotic behavior and classifying singularities.

DefinitionInfinite Limits

We write limxaf(x)=\lim_{x \to a} f(x) = \infty if for every M>0M > 0, there exists δ>0\delta > 0 such that 0<xa<δ    f(x)>M0 < |x - a| < \delta \implies f(x) > M

Similarly, limxaf(x)=\lim_{x \to a} f(x) = -\infty means for every M<0M < 0, there exists δ>0\delta > 0 such that 0<xa<δ    f(x)<M0 < |x - a| < \delta \implies f(x) < M

These definitions formalize the idea that f(x)f(x) grows arbitrarily large (or decreases without bound) as xx approaches aa. The vertical line x=ax = a is called a vertical asymptote of ff.

ExampleInfinite Limit at a Point

Consider f(x)=1x2f(x) = \frac{1}{x^2} as x0x \to 0. For any M>0M > 0, we need 1x2>M\frac{1}{x^2} > M, which is equivalent to x2<1Mx^2 < \frac{1}{M}, or x<1M|x| < \frac{1}{\sqrt{M}}. Choosing δ=1M\delta = \frac{1}{\sqrt{M}} works, so limx01x2=\lim_{x \to 0} \frac{1}{x^2} = \infty This confirms that x=0x = 0 is a vertical asymptote.

DefinitionLimits at Infinity

We say limxf(x)=L\lim_{x \to \infty} f(x) = L if for every ϵ>0\epsilon > 0, there exists N>0N > 0 such that x>N    f(x)L<ϵx > N \implies |f(x) - L| < \epsilon

Similarly, limxf(x)=L\lim_{x \to -\infty} f(x) = L means for every ϵ>0\epsilon > 0, there exists N<0N < 0 such that x<N    f(x)L<ϵx < N \implies |f(x) - L| < \epsilon

The horizontal line y=Ly = L is called a horizontal asymptote of ff.

ExampleLimit at Infinity

Consider limx2x2+3x+1x2+5\lim_{x \to \infty} \frac{2x^2 + 3x + 1}{x^2 + 5}. Dividing numerator and denominator by x2x^2: 2x2+3x+1x2+5=2+3x+1x21+5x2\frac{2x^2 + 3x + 1}{x^2 + 5} = \frac{2 + \frac{3}{x} + \frac{1}{x^2}}{1 + \frac{5}{x^2}}

As xx \to \infty, the terms 3x\frac{3}{x}, 1x2\frac{1}{x^2}, and 5x2\frac{5}{x^2} all approach 0, so limx2x2+3x+1x2+5=2+0+01+0=2\lim_{x \to \infty} \frac{2x^2 + 3x + 1}{x^2 + 5} = \frac{2 + 0 + 0}{1 + 0} = 2

Remark

When evaluating limits of rational functions at infinity, the dominant terms (highest powers) determine the behavior:

  • If degrees are equal, the limit is the ratio of leading coefficients
  • If numerator has higher degree, the limit is ±\pm\infty
  • If denominator has higher degree, the limit is 0
DefinitionInfinite Limits at Infinity

We can combine these concepts: limxf(x)=\lim_{x \to \infty} f(x) = \infty means for every M>0M > 0, there exists N>0N > 0 such that x>Nx > N implies f(x)>Mf(x) > M. This describes functions that grow without bound as xx increases without bound, such as f(x)=x2f(x) = x^2 or f(x)=exf(x) = e^x.

Understanding these various types of limiting behavior provides a complete picture of how functions behave both locally (near specific points) and globally (as variables tend to infinity).