ConceptComplete

Exact Sequences and Excision - Core Definitions

Exact sequences provide the algebraic framework for computing homology through decomposition, while excision enables cutting and pasting arguments.

Definition

A sequence of abelian groups and homomorphisms ⋯→An+1→fn+1An→fnAn−1→⋯\cdots \to A_{n+1} \xrightarrow{f_{n+1}} A_n \xrightarrow{f_n} A_{n-1} \to \cdots is exact at AnA_n if im(fn+1)=ker⁡(fn)\text{im}(f_{n+1}) = \ker(f_n). The sequence is exact if it's exact at every group.

Exactness means "the image equals the kernel": elements mapped to zero are precisely those coming from the previous map. This captures algebraic dependencies systematically.

Example

A short exact sequence 0→A→fB→gC→00 \to A \xrightarrow{f} B \xrightarrow{g} C \to 0 means:

  • ff is injective (since ker⁡(f)=im(0)=0\ker(f) = \text{im}(0) = 0)
  • gg is surjective (since im(g)=ker⁡(0)=C\text{im}(g) = \ker(0) = C)
  • im(f)=ker⁡(g)\text{im}(f) = \ker(g), so C≅B/im(f)C \cong B / \text{im}(f)
Definition

For a pair (X,A)(X, A), the long exact sequence of the pair is: ⋯→Hn(A)→i∗Hn(X)→j∗Hn(X,A)→∂Hn−1(A)→⋯\cdots \to H_n(A) \xrightarrow{i_*} H_n(X) \xrightarrow{j_*} H_n(X, A) \xrightarrow{\partial} H_{n-1}(A) \to \cdots

Here i:A↪Xi : A \hookrightarrow X is inclusion, j:X→(X,A)j : X \to (X, A) is the quotient map, and ∂\partial is the connecting homomorphism.

The connecting map ∂:Hn(X,A)→Hn−1(A)\partial : H_n(X, A) \to H_{n-1}(A) has degree −1-1 and is natural. It's constructed from the snake lemma applied to the short exact sequence of chain complexes 0→C∙(A)→C∙(X)→C∙(X,A)→00 \to C_\bullet(A) \to C_\bullet(X) \to C_\bullet(X, A) \to 0.

Theorem

(Excision Theorem) Let X=A∪BX = A \cup B where Z‾⊆int(A)\overline{Z} \subseteq \text{int}(A) for some Z⊆A∩BZ \subseteq A \cap B. Then excising ZZ induces isomorphisms: Hn(X∖Z,A∖Z)→≅Hn(X,A)H_n(X \setminus Z, A \setminus Z) \xrightarrow{\cong} H_n(X, A) for all nn. Cutting out ZZ doesn't affect relative homology.

Example

Write Sn=D+n∪D−nS^n = D^n_+ \cup D^n_- (hemispheres). Excise a small disk around a point in D−n∖Sn−1D^n_- \setminus S^{n-1}. Then: Hn(Sn,D−n)≅Hn(D+n,Sn−1)H_n(S^n, D^n_-) \cong H_n(D^n_+, S^{n-1}) The right side is Hn(D+n/Sn−1)=Hn(Sn)H_n(D^n_+/S^{n-1}) = H_n(S^n) since collapsing the boundary gives SnS^n.

Definition

A split exact sequence is a short exact sequence 0→A→B→C→00 \to A \to B \to C \to 0 where B≅A⊕CB \cong A \oplus C (as groups, not canonically). Splitting means there's a section C→BC \to B or retraction B→AB \to A.

Remark

Exact sequences encode how algebraic objects decompose. The long exact sequence of a pair shows that Hn(X,A)H_n(X, A) measures the "difference" between Hn(X)H_n(X) and Hn(A)H_n(A). Excision says this difference is local, depending only on neighborhoods.